36q^2-1089=0

Solution for 36q^2-1089=0 equation:

36q^2-1089=0

a = 36; b = 0; c = -1089;
Δ = b2-4ac
Δ = 02-4·36·(-1089)
Δ = 156816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{156816}=396$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-396}{2*36}=\frac{-396}{72}
=-5+1/2
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+396}{2*36}=\frac{396}{72}
=5+1/2
$